ChemBench
Gay-Lussac's Law Calculator
Heat a sealed container, pressure climbs.
Gay-Lussac's law: pressure against temperature at fixed volume
P1/T1 = P2/T2, with temperature in kelvin. Heating a sealed rigid container raises the pressure proportionally.
| Initial pressure | Initial temperature | New temperature | New pressure |
|---|---|---|---|
| 1 atm | 273.15 K (0 C) | 546.30 K | 2.0000 atm |
| 1 atm | 273.15 K (0 C) | 373.15 K (100 C) | 1.3661 atm |
| 1 atm | 293.15 K (20 C) | 373.15 K (100 C) | 1.2729 atm |
| 2 atm | 300 K | 450 K | 3.0000 atm |
| 3 atm | 298.15 K (25 C) | 323.15 K (50 C) | 3.2516 atm |
This is the law behind warnings not to leave aerosol cans in a hot car: a jump from 20 C to 100 C raises the internal pressure by more than a quarter.
Pressure tracks temperature in a fixed volume
When a gas can't expand, raising its temperature forces its pressure up proportionally — this is why aerosol cans warn against heat exposure, and why tire pressure rises on a hot day.
A safety-relevant law
Understanding this relationship is why pressure vessels have temperature limits — a sealed rigid container heated enough can build pressure well past its rated capacity.
Frequently asked questions
A sealed gas cylinder reads 30 psi at 20°C — what will the pressure be at 50°C?
Convert to Kelvin: T1 = 293 K, T2 = 323 K. P2 = P1 × T2/T1 = 30 × 323/293 = 33.1 psi.
How is Gay-Lussac's law different from Charles's law?
Both link temperature to another gas property. Charles's law tracks volume changes at constant pressure (flexible container). Gay-Lussac's law tracks pressure changes at constant volume (rigid container). Use the Charles's law calculator for expandable systems.
Why do tires lose pressure in winter?
Cold temperatures lower air pressure inside the tire per Gay-Lussac's law. A tire at 35 psi in 30°C summer heat drops to about 32 psi at 0°C — roughly 1 psi lost per 5.5°C temperature drop.
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OpenLast updated: September 7, 2026