Loading…
Loading…
ChemBench
Extract Ea from two experimental data points.
Measuring a reaction's rate constant at two different temperatures lets you solve directly for activation energy, without ever needing to know the pre-exponential factor A.
This two-temperature method is exactly how activation energies are measured experimentally — run the same reaction at two temperatures, time it, and solve for Ea from the rate constants.
Molar mass of any chemical formula (e.g. H2O, C6H12O6, Ca(OH)2).
OpenPercent composition of an element within a chemical formula.
OpenSimplest whole-number ratio formula from elemental masses or percentages.
OpenPercent yield from actual and theoretical reaction yields.
OpenActivation energy
91,889.724 J/mol
What you entered
ln(k₂ ÷ k₁)
ln(0.01 ÷ 0.001)= 2.3026Ea = −R × ln(k₂/k₁) ÷ (1/T₂ − 1/T₁)
−8.314 × 2.3026 ÷ (1/320 − 1/300)= 91889.7238 J/molResult
Activation energy: 91,889.724 J/mol
The reaction's activation energy is 91,889.724 J/mol.