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MotionLab
How much charge a capacitor can store for a given voltage — the foundation of energy storage in circuits.
Capacitance increases with larger plate area (more room for charge), smaller gap (stronger field), and higher dielectric constant (the insulating material between plates polarizes and effectively multiplies the capacitance) — real capacitor design is about optimizing all three.
Inserting a dielectric material (κ > 1) between the plates increases capacitance without changing the physical size — water has κ ≈ 80, which is why it's such a good solvent for ionic compounds, and ceramic capacitors use materials with κ in the thousands.
Capacitance (F)
0
C = κε₀A/d
What you entered
C = κε₀A ÷ d
1 × 8.854e-12 × 0.01 ÷ 0.001= 8.8542e-11 FCharge Q = CV (at 1 V)
8.8542e-11 × 1= 8.8542e-11 CEnergy E = ½CV² (at 1 V)
0.5 × 8.8542e-11 × 1²= 4.4271e-11 JResult
Capacitance (F): 0
A parallel-plate capacitor with 0.01 m² plates, 0.001 m gap, and κ = 1 has a capacitance of 8.8542e-11 F.