DistCalc

Midpoint Calculator

M = ((x₁+x₂)/2, (y₁+y₂)/2).

x₁

y₁

x₂

y₂

Midpoint x

M = ((x₁+x₂)/2, (y₁+y₂)/2)

Midpoint y: 2

What you entered

x₁: 0y₁: 0x₂: 6y₂: 4

1
Midpoint x
(0 + 6) ÷ 2= 3
2
Midpoint y
(0 + 4) ÷ 2= 2

Result

Midpoint x: 3

The midpoint between (0, 0) and (6, 4) is (3, 2).

Midpoint between two points

The midpoint is the average of the x coordinates and the average of the y coordinates, taken separately.

Point 1	Point 2	Midpoint
(0, 0)	(4, 6)	(2.00, 3.00)
(1, 2)	(5, 8)	(3.00, 5.00)
(-3, 4)	(7, -2)	(2.00, 1.00)
(2, 2)	(10, 10)	(6.00, 6.00)
(-5, -5)	(5, 5)	(0.00, 0.00)

Negative coordinates work exactly the same way, as the third and fifth rows show - averaging -5 and 5 gives 0, so two points symmetric about the origin have their midpoint at the origin. The order of the points does not matter, since averaging is commutative. The midpoint is not the same as the distance between the points: it is a location, not a length, which is why the answer is a coordinate pair rather than a single number.

Just an average, in two dimensions

The midpoint formula is nothing more than averaging the x-coordinates and averaging the y-coordinates separately — the point exactly halfway between two others on both axes at once.

Practical uses

Finding the center of a line for construction layouts, splitting a route into two equal legs, or locating the balance point between two coordinates on a map or diagram.

Frequently asked questions

How do I find the midpoint between two points?

Midpoint = ((x₁+x₂)/2, (y₁+y₂)/2). For points (2, 8) and (6, 4): M = ((2+6)/2, (8+4)/2) = (4, 6). It's simply the average of the x-coordinates and the average of the y-coordinates.

What is the midpoint used for?

Finding the center of a line segment, bisecting a shape, locating the balance point between two locations, placing something equidistant from two reference points, and dividing a route into two equal halves.

Can I find a point that divides a segment in a ratio other than 1:1?

Yes — use the section formula. For ratio m:n between (x₁,y₁) and (x₂,y₂): x = (mx₂ + nx₁)/(m+n), y = (my₂ + ny₁)/(m+n). The midpoint is the special case where m:n = 1:1.